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Q:
How to create a not null constraint for angular model/data
I have an array of objects as the model in Angular and am trying to find a way to enforce that each object has at least 1 element within the array. I can add a [DisplayName] attribute and reference the model like so:
Create
@model List
@foreach(var t in Model)
{
@*do something*@
}
Currently, I can include [Required] to require the field to be set and it behaves like this, but I can still manually set it to null or omit it and run this and I expect [DisplayName] to error like so:
Update
@model List
@{
var model = Model;
}
@foreach(var t in model)
{
@t.Description
}
If I omit the [Required] attribute I get a [System.ArgumentNullException]. If I omit the [DisplayName] attribute and I try and run the update I get the same error. Is there a way to make this work by default?
A:
You have to override the EditorForModelMetadata method of the DisplayTemplate. Since this method gets called whenever the Razor template is building the display, you have to use the DisplayForModelMetadata method that will only be called if the property in question is null.
To define a template for your model, add a template for your field in the class of your model. And create a DisplayForModelMetadata method:
public class TestModel
{
[Required]
public string Description { get; set; }
}
DisplayTemplate.ascx
@model TestModel
@Html.DisplayForModel()
4. Intel® and Intel® Centrino®-based Dual Band Wireless-N PCI Adapter:. Mar 28, 2011. Since the ACPD6110 is a Linux compatible PCI wireless adapter, we will use this as an example to show how to install Intel® Wireless AC 200.Q: How to count number of each items within all groups? I have a dataset like the following. ID | Class | Date =================== 1 | A | 1/1/2015 2 | A | 2/2/2015 3 | A | 3/3/2015 4 | B | 1/1/2015 5 | B | 2/2/2015 6 | B | 3/3/2015 7 | C | 1/1/2015 8 | C | 2/2/2015 9 | C | 3/3/2015 10 | C | 4/4/2015 I want to find out For each ID, I want to find out the number of times it falls into each Class. For example, in the above case, the results are: ID | A | B | C ====================== 1 | 2 | 1 | 0 2 | 1 | 0 | 0 3 | 0 | 0 | 1 4 | 0 | 1 | 0 7 | 0 | 0 | 1 8 | 0 | 0 | 0 9 | 0 | 0 | 0 10 | 1 | 0 | 0 A: Here’s a way with data.table: DT f30f4ceada
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